Question
From a watch tower of 150 m height, the angles of
depression of two cliffs in a horizontal line through the base of the tower are 45° and 30°. Find the distance between the cliffs if they are on the same side.Solution
In triangle ABC- Tan45 150/AC AC =150m Now – Tan30 =150/AD 1/√3 =150/AD AD=150√3. Distance between the cliffs = AD=AC+CD 150√3 =150+CD CD=150√3-150 =150(√3-1) m
If n(A) = 25, n(B) = 40 and n(A ∪ B) = 50, then n(A ∩ B) equals
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