Question
Bag X contains 2 red balls and 6 blue balls, whereas
bag Y contains 3 red balls and 2 blue balls. One ball is drawn at random from X and transferred into Y. Two balls are now drawn at random from Y. Find the probability that both balls are of different colours.Solution
Required probability
= (2/8) X 2 X (4/6) X (2/5) + (6/8) X 2 X (3/6) X (3/5) = (1/4) X (16/30) + (3/4) X (18/30) = (16/120) + (54/120) = (70/120) = (7/12)
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