Question
Two hats are picked at random, what is the probability
that one is blue and one is yellow? A box contains 6 red, 4 blue, 2 green and 4 yellow hats.Solution
Total number of hats = 6 + 4 + 2 + 4 = 16 Let S be the sample space. Then, n(S) = number of ways of drawing 2 hats out of 16 = ¹⁶C_2 = (16 × 15 )/(2 × 1) = 120 Let E= event of drawing two hats so that one is blue and one is yellow. n(E) = ⁴C_1×⁴C_1 = 4 × 4 = 16 ∴ P (E) = (n(E))/(n(S)) = 16/120 = 2/15
5/13 × 104 + 1(2/9) × 198 = 133 + ?
What will come in the place of question mark (?) in the given expression?
(24 2 – 16 2 ) + 75% of 40% of 480 = ?
5 + 2 × 3 ÷ (3 × 2) ÷ 4
Find the Value of √(-√3+√(3+8√(7+4√3)))?
- What will come in the place of question mark (?) in the given expression?
35% of 400 - 20% of 300 = (? - 30) X 2 15848 ÷ 4 – 793 × 6 + 3628 = 3 × ?
? = (22% of 25% of 60% of 3000) + 21
What will come in place of the question mark (?) in the following expression?
(320 ÷ 8 + 22) × 4 = 60 + 40% of ?
70 % of 640 + 75 % of 360 - 19 × 12 = ?
24 × ?2 – 11 × 4 = 1900
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