Question
Two hats are picked at random, what is the probability
that all hats are of green colour? A box contains 6 red, 4 blue, 2 green and 4 yellow hats.Solution
Total number of hats = 6 + 4 + 2 + 4 = 16 Let S be the sample space. Then, n(S) = number of ways of drawing 2 hats out of 16 = ¹⁶C_₂ = (16 × 15)/( 2 × 1) = 120 Let E= event of drawing all the hats are of green colour n(E) = ²C_₂ = 1 ∴ P (E) = (n(E))/(n(S)) = 1/120
? = 21.91% of (36.2 × (144.01 + 5.95)) + 16.71
(3375)1/3 x 12.11 x 6.97divide; 14.32 = ? + 15.022
(√899.69 + 49.83% of 640.24)² - (7/8 of 479.79) = ?
75.22 of 219.98% + 359.99 ÷ 18.18 = ?
14.99% of 7820 + 5535.25 ÷ 123.001 - ? = 84
70.008% of 399.98 + ?% of 399.999 = 80.105% of 599.998
(15.022% of 20) × 46 ÷ 2.03 – 8.78 × 5.72 + 50.23% of 4820 = ?
20.05% of 450.05 – 15.15% of 119.99 × 4.02 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
?2/3 = 33.33% of 107.99 + 45.45