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Numbers of bananas = Numbers of rotten bananas + Numbers of good bananas ∴ Total number of bananas = 136 + 22 = 158 bananas P(E) = (Number of favourable outcomes) / (Total number of outcomes) P(picking a good banana) = 136/158 = 68/79
1595, 1083, 740, 524, 399, ?
17 21 51 169 701 ?
17, 19, 41, 127, 513, ?
What will be come in place of (?) in the given number series.
2, 3, 5, 7, 11, ?, 17
116, 118, 124, 136, 156, ?
6400, 1600, ?, 80, 16, 4
4 10 ? 62.5 156.25 390.625
...51 26 27 ? 86 217.5
120 124 151 167 292 ?
4.8, 14, 62, ?, 1516, 7578