Question
22 rotten bananas are accidentally mixed with 136 good
ones. It is not possible to just look at a banana and tell whether or not it is rotten. One banana is taken out at random from this lot. Determine the probability that the banana is taken out is a good one.Solution
Numbers of bananas = Numbers of rotten bananas + Numbers of good bananas ∴ Total number of bananas = 136 + 22 = 158 bananas P(E) = (Number of favourable outcomes) / (Total number of outcomes) P(picking a good banana) = 136/158 = 68/79
More Probability Questions
(30 × 0.80)⁴ ÷ (2160 ÷ 60)⁴ × (54 × 16)⁴ = (6 × 4)?+5
3/7 of 504 ÷ 12 + 17 = √?
20% of 150 + 30 X 4 = ? X 5
52% of 400 + √(?) = 60% of 600 - 25% of 400
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
15 * 12 + 35% of 80 + 70% of 130 = ?
60 % of 640 - 57 × 2 - 1520 / 38 = ?
- Find the simplified value of the given expression:
10 of 5 ÷ 4 × 2² + √25 – 8 (168 ÷ 12 + 19 × 64)/(22+1) = ?
