A bag has balls of three colours. It has 8 red balls, x green balls and y blue balls, If probability of picking one green ball and that of picking one blue ball out of bag is equal. Then, find the number of blue balls if probability of picking one red ball is 1/2.
Number of green balls and y balls are same in the bag 8C1/(x+y+8)C1 = 1/2 here x = y 8/(2x + 8) = 1/2 x = 4 so, number of blue balls = 4
2380.03 ÷ 84.98 x 39.9 = ? + 15.32
(22.03 + 89.98) ÷ 14.211 = 89.9 – 25.23% of ?
`11(2/13)` + `5(2/11)` - `3(4/9)` = ?
13³ + 1.3² + 1.03¹ + 1.003 = ?
6401.23 × `1 3/4` - 352.87 × ? = 10443.789
√ ({(5.5× 2.3)× √ (728.91))} = 3(1/7)÷ ?/28
...739.85 + 5003 ÷ 24.99 × 69.999 = ?
(16.16 × 34.98) + 14.15% of 549.99 = ? + 124.34
(24.88% of 4879.79) + 20.030 × 13.88 of 13.86 + 46.21 = ? + (13.22)²
90.004% of 9500 + 362 = ?
