Question
From a watch tower of 205 m height, the angles of depression of two cliffs in a horizontal line through the base of the tower are 45° and 30°. Find the distance between the cliffs if they are on the same side.
In triangle ABC- Tan45 =205/AC AC =205m Now – Tan30 =205/AD 1/ √3 =205/AD AD=205√3. Distance between the cliffs = AD=AC+CD 205 √3 =205+CD CD=205√3-205 =205(√3-1) mMore Height and Distance Questions
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