Question
From a watch tower of 205 m height, the angles of
depression of two cliffs in a horizontal line through the base of the tower are 45° and 30°. Find the distance between the cliffs if they are on the same side.Solution
In triangle ABC- Tan45 =205/AC AC =205m Now – Tan30 =205/AD 1/ √3 =205/AD AD=205√3. Distance between the cliffs = AD=AC+CD 205 √3 =205+CD CD=205√3-205 =205(√3-1) m
26 63 124 215 342 511 ?
...14 8 6 4 7 8.5
...12Â Â Â Â Â Â Â Â Â Â Â Â Â 10Â Â Â Â Â Â Â Â Â Â Â Â 13Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 18.5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 25.50Â Â Â Â Â Â Â ...
If 10 9 38 x 5428
Then, 2x² + 1 = ?
...2, 12, 90, 240, ?, 1260
620 632 608 644 596 ?
...60000 2400 120 8 0.8 ?
...In each of the following questions, a number series is given. After the series a number is given followed by (a), (b), (c), (d) and (e). You have to com...
18 Â Â Â Â 32 Â Â Â 50 Â Â Â 72 Â Â Â Â 98 Â Â Â Â ?
5184, ?, 432, 144, 36, 12