Question
From a watch tower of 205 m height, the angles of
depression of two cliffs in a horizontal line through the base of the tower are 45° and 30°. Find the distance between the cliffs if they are on the same side.Solution
In triangle ABC- Tan45 =205/AC AC =205m Now – Tan30 =205/AD 1/ √3 =205/AD AD=205√3. Distance between the cliffs = AD=AC+CD 205 √3 =205+CD CD=205√3-205 =205(√3-1) m
More Height and Distance Questions
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560 ÷ 14 × 3 – 25 = ?
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48 × 1...
55% of ? = 45 + 20 × 6
What will come in place of the question mark (?) in the following expression?
46 – 5² + 8² + 3² = ? × 4
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