Question
From a watch tower of 205 m height, the angles of
depression of two cliffs in a horizontal line through the base of the tower are 45Β° and 30Β°. Find the distance between the cliffs if they are on the same side.Solution
In triangle ABC- Tan45 =205/AC AC =205m Now β Tan30 =205/AD 1/ β3 =205/AD AD=205β3. Distance between the cliffs = AD=AC+CD 205 β3 =205+CD CD=205β3-205 =205(β3-1) m
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