From a watch tower of 205 m height, the angles of depression of two cliffs in a horizontal line through the base of the tower are 45° and 30°. Find the distance between the cliffs if they are on the same side.
In triangle ABC- Tan45 =205/AC AC =205m Now – Tan30 =205/AD 1/ √3 =205/AD AD=205√3. Distance between the cliffs = AD=AC+CD 205 √3 =205+CD CD=205√3-205 =205(√3-1) m
If 4 2 x 1.5 0.5
Then, 1/3 x + 2.5 = ?
81, 90, 108, 135, 171, ?
625, 5, 125, 25, 25, ? , 5
6 10 ? 210 1672 16710
...412, 537, 573, 916, 980, ?
140 300 380 420 440 ?
...542 541 532 507 458 ?
...If 4 x 4 7 15 38.5
Then, ( x + 1) ( x - 1) = ?
...95 110 128 ? 181 222
...21, 22, 48, 153, 628, ?
