Question
There are two houses of the same height on both sides of
a 30-meter wide road. From a point on the road, elevation angles of the houses are 30° and 60° respectively. Find the height of the houses.Solution
Let y be the height of the houses, here AB = CD = y meter. Let x be the distance between the point on the road and the house making an elevation angle of 60°, here BE = x meter. Then, (30 - x) is the distance between the point on the road from the house making an elevation angle 30°, here DE = (30 - x) meter. Now, tan 60° = AB/BE ⇒ √3 = y/x ⇒ x = y/√3 ...(i) Also, tan 30° = CD/DE ⇒ 1/√3 = y/(30 - x) ⇒ √3y = 30 - x ⇒ √3y = 30 - y/√3 [from equation i] ⇒ 3y = 30√3 - y ⇒ 4y = 30√3 ⇒ y = 30√3/4 ≈ 12.9 meter
5/2 of 5/6 of 12/5 of 54 % of 5250 = ?
?% of (√196) × 24 + 344 = 428
961 × 4 ÷ 31 – 15% of 180 = ? – 73
(75 + 0.25 × 10) × 4 = ?2 - 14
(64/25)? × (125/512)?-1 = 5/8
Simplify the following expression:
  (400 +175) ² - (400 – 175) ² / (400 × 175)
What will come in the place of question mark (?) in the given expression?
34 X 11 - ? + 36 = 3 X 75 + 125
√256 × 25 – 15 × 14 =?
Find the simplified value of the given expression.
18 ÷ 3 + {(48 ÷ 6) of 12} + 10 - 8 of 9
- What will come in place of (?), in the given expression.
(28 × 4) + (96 ÷ 4) – 25 = ?