Question
There are two houses of the same height on both sides of
a 40-meter wide road. From a point on the road, elevation angles of the houses are 30Β° and 60Β° respectively. Find the height of the houses.Solution
Let y be the height of the houses, here AB = CD = y meter. Let x be the distance between the point on the road and the house making an elevation angle of 60Β°, here BE = x meter. Then, (40 - x) is the distance between the point on the road from the house making an elevation angle 30Β°, here DE = (40 - x) meter. Now, tan 60Β° = AB/BE β β3 = y/x β x = y/β3 Β ...(i) Also, tan 30Β° = CD/DE β 1/β3 = y/(40 - x) β β3y = 40 - x β β3y = 40 - y/β3 Β [from equation i] β 3y = 40β3 - y β 4y = 40β3 β y = 40β3/4 β 17.3 meter
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