Question
From the top of an upright pole 30√3 feet high, the
angle of elevation to the top of an upright tower was 60°. If the foot of the pole was 55 feet away from the foot of the tower, what is the height of the tower?Solution
The height of poll AB= 30√3 =AB=DC=30√3 AD=BC=55feet Let ED=x Then Tan60 = ED/AD √3=x/55 X=55√3 Now -the height of the tower CE=ED+DC=55√3+30√3 =85√3feet
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?, 26, 38, 70, 130, 226
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7 47 ? 223 359 527
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5, 12, 24, 36, 52, ?
What will come in place of the question mark (?) in the following series?
1.5, 3.5, 9.5, 27.5, 81.5, 243.5, ?
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