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    Question

    From the top of an upright pole 30√3 feet high, the

    angle of elevation to the top of an upright tower was 60°. If the foot of the pole was 55 feet away from the foot of the tower, what is the height of the tower?
    A 75√3feet Correct Answer Incorrect Answer
    B 85√3feet Correct Answer Incorrect Answer
    C 55√3feet Correct Answer Incorrect Answer
    D 74√3feet Correct Answer Incorrect Answer

    Solution

    The height of poll AB= 30√3 =AB=DC=30√3 AD=BC=55feet Let ED=x Then  Tan60 = ED/AD √3=x/55 X=55√3 Now -the height of the tower  CE=ED+DC=55√3+30√3 =85√3feet

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