Question
From the top of an upright pole 30√3 feet high, the
angle of elevation to the top of an upright tower was 60°. If the foot of the pole was 55 feet away from the foot of the tower, what is the height of the tower?Solution
The height of poll AB= 30√3 =AB=DC=30√3 AD=BC=55feet Let ED=x Then Tan60 = ED/AD √3=x/55 X=55√3 Now -the height of the tower CE=ED+DC=55√3+30√3 =85√3feet
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