Question
From the top of an upright pole 30√3 feet high, the
angle of elevation to the top of an upright tower was 60°. If the foot of the pole was 55 feet away from the foot of the tower, what is the height of the tower?Solution
The height of poll AB= 30√3 =AB=DC=30√3 AD=BC=55feet Let ED=x Then Tan60 = ED/AD √3=x/55 X=55√3 Now -the height of the tower CE=ED+DC=55√3+30√3 =85√3feet
A market in which there are large numbers of sellers of a particular product, but each seller sells somewhat differentiated but close products is termed...
The purchase of shares and bonds of Indian companies by Foreign Institutional Investors is called?
With reference to the BRICS, consider the following statements-Â
I. The BRICS brings together five of the largest developing countries of the wo...
GI tag in India is issued by _____________.
Consider the following statements regarding Pradhan Mantri Jan Aarogya Yojana (PM-JAY):
I. It targets the beneficiaries as identified by Socio-Ec...
In which year Bombay Stock Exchange was established?
The cost of unit assistance is shared between Central and State Governments in the ratio ________ in plain areas and 90:10 for North Eastern and hilly s...
The ‘Mudra Bank’ is a subsidiary of—Â
Which of the following best describes the primary purpose of the ASBA process?
The terms ‘Marginal Standing Facility Rate’ and ‘Net Demand and Time Liabilities’, sometimes appearing in news, are used in relation to?
...
Relevant for Exams:
