Question
The angle of depression from the top of a light-house
of two boats are 60° and 30° towards the west, if the two boats are 60m apart, then the height of the light house isSolution
D = h (cotA - cotB) Here (h = height of light house) D = AB = 60 60 = h (cot30° - cot60°) 60 = h (√3-1/√3) 60 = h ((3-1)/√3) 2h/√3 = 60 m     h = 60 × √3/2 = 30√3 m So height of the tower is = 30√3 m
(424.98 ÷ 16.99 + ?) × 1.99 - 211.99 ÷ 2.01 = 24.98 × (4.012 - 3.99)Â
12.052 + 36.15 × 25.45 – 124.15 × 15.05 = ? × 8.08 – 64.32 × 15.98
?% of (95.31 ÷ 18.97 × 70.011) = 174.98
(15.98% of 399.99) - 6.998 = √?
111.89 × 4.12 – 504.04 ÷ 2.12 = 170.12 + ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
20.06% of 359.89 - 15.95 X ? + 18.07 X 14.95 = 48.87 X 6.02
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?
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