Question
The angle of elevation of a tower from a certain point of bus stand is 30°. When a man walks 5m ahead in the direction of the tower, the angle of elevation becomes 60°. What is the height of the tower?
More Height and Distance Questions
- A vertical pole and a vertical tower are standing on the same level ground. Height of the pole is 15 metres . From the top of the pole the angle of elevati...
- From a point 20 m away from the foot of a pole, the angle of elevation of the top of the pole is 60 degrees. Find the height of the pole.
- In the village of Hazelton, there was a totem pole 50 m high of which the lower 24 m was carved. According to a clue the treasure was hidden at a point on ...
- From a point on the ground, the angle of elevation of the top of a tower is 30 degrees. After moving 10√3 m towards the tower, the angle becomes 60 degrees...
- The two buildings are 100m apart. From the top of the first building, which is 60m tall, the angle of depression to the top of the second building is 45 de...
- The angle of depression of a point on the ground as seen from the top of a tower, 20 feet high, is 45°. Find the distance of the point on the ground from t...
- A pole 9√3 m high casts a shadow 27 m long on the ground. Find the angle of elevation
- A tree of height 'h' meters is partially bent at a certain point above the ground, causing its top to touch the ground at a distance of 12 meters from its ...
- A vertical tower stands on a horizontal plane and is surmounted by a vertical flag staff of height h. At a point on the plane, the angle of elevation of th...
- From a point situated at some distance from the base of a pillar, the angle of elevation of the top of the pillar is found to be 45 degrees. After walking ...
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)
Let, the height of the post = AB = ‘h’ m From ΔACB, ∠ACB = 30° [∵ given] tan ∠ACB = perpendicular/base ⇒ tan 30° = AB/BC ⇒ 1/√3 = h/BC ⇒ BC = h√3 ... (1) From ΔADB, ∠ADB = 60° [∵ given] tan ∠ADB = perpendicular/base ⇒ tan 60° = AB/BD ⇒ √3 = h/BD ⇒ BD = h/√3 ... (2) According to the question: BC - BD = 5 ⇒ h√3 - h/√3 = 5 ⇒ 2h/√3 = 5 ⇒ h = (5√3)/2 m