Question
A shadow of a tower standing on level ground is found to
be 40√3 meters longer when the Sun's altitude is 30° than when it is 60°. The height of the tower is:Solution
ATQ, Let the height of the tower be h . The difference in shadow lengths is given as 40√3 :
Solving this gives:
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Simplify:- 50÷5×2+10−6