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      Question

      The height of a conical tent is 9m. A vertical pole of

      6m height is placed 4 m away from its centre such that it touches the surface. Find the slant height of the tent from the base to the point where the pole touches it?
      A 5m Correct Answer Incorrect Answer
      B 10m Correct Answer Incorrect Answer
      C 15m Correct Answer Incorrect Answer
      D 18m Correct Answer Incorrect Answer

      Solution

      Since, triangle’s are similar, AD/AB = DE/BC 3/9 = 4/BC BC = 12m In â–³ ABC, AC = √(AB2 + BC2)) = √(92 + 122) = √(81+144) = √225 = 15 m In â–³ ADE, AE = √(AD2 + DE2) = √(32 + 42) = √(9+16) = √25 = 5 m i.e., CE = AC – AE = 15 – 5 = 10 m

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