Question
From a point on the ground, the angle of elevation of
the top of a tower is 30 degrees. After moving 20 m towards the tower, the angle becomes 60 degrees. The height of the tower is:Solution
ATQ, Let the distance from the nearer point to the tower be x m. Then height = x tan 60 = x√3 From the farther point, distance = x + 20 So height = (x + 20) tan 30 = (x + 20)/√3 Therefore, x√3 = (x + 20)/√3 3x = x + 20 2x = 20 x = 10 Height = 10√3 m
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