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    Question

    (I) 4x2 = 25 (II) 2y2 - 13y + 21 =

    0 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;
    A x < y Correct Answer Incorrect Answer
    B x > y Correct Answer Incorrect Answer
    C x=y Correct Answer Incorrect Answer
    D x≥y Correct Answer Incorrect Answer
    E x≤y Correct Answer Incorrect Answer

    Solution

    1. 4x2 = 25 or x = +- 5/2
    2. 2y2 - 13y + 21= 0 , or 2y2 - 6y - 7y + 21= 0
    ( y – 3) (2y – 7) = 0, or y = 3 7/2, Hence, y> x

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