Question
If x sin3 θ + y cos3 θ = sin θ
cos θ and x sin θ − y cos θ = 0, then the value of x2 + y2 equalsSolution
x sin3 θ + y cos3 θ = sin θ cos θ -> eq 1 x sin θ − y cos θ = 0 x sin θ = y cos θ -->eq2 substituting in eq1 y cos θ sin2 θ + y cos3 θ = sin θ cos θ taking y cos θ common y cos θ(sin2 θ + cos2 θ) = sin θ cos θ { we know sin2 θ + cos2 θ =1} y cos θ = sin θ cos θ y = sin θ substituting in eq 2 x sin θ = sin θ cos θ x = cos θ x2 + y2 sin2 θ + cos2 θ = 1
23Â Â Â 30Â Â Â Â 44Â Â Â Â 65Â Â Â Â Â 92Â Â Â Â Â 128
1728, 1762, 1804, 1854, 1912, 1978
32, 41, 66, 115, 236, 415
Find the wrong number in the given number series.
548, 532, 568, 510, 604, 460
850, 849, 841, 814, 750, 688
Find the wrong number in the given number series.
6, 24, 120, 720, 5041, 40320
132, 148, 196, 340, 762, 2068
Find the wrong number in the given number series.
630, 180, 60, 24, 12, 8, 5- Find the wrong number in the given number series.
6, 14, 42, 105, 230, 446 4178, 2153, 928, 303, 78, 55Â Â