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    Question

    Which is the largest six digit number, which when

    divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26 respectively.
    A 999956 Correct Answer Incorrect Answer
    B 999960 Correct Answer Incorrect Answer
    C 999964 Correct Answer Incorrect Answer
    D 999982 Correct Answer Incorrect Answer

    Solution

    ATQ, LCM of 12, 15, 20, 24, 30 is 120  As we know, (12 – 8) = (15 – 11) = (20 – 16) = (24 – 20) = (30 – 26) = 4  As we know, 6 digit largest number = 999999  So, number divisible by 120 = 999999 – 39 = 999960  Required number is = 999960 – 4 = 999956

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