Question
Which is the largest six digit number, which when
divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26 respectively.Solution
ATQ, LCM of 12, 15, 20, 24, 30 is 120 As we know, (12 – 8) = (15 – 11) = (20 – 16) = (24 – 20) = (30 – 26) = 4 As we know, 6 digit largest number = 999999 So, number divisible by 120 = 999999 – 39 = 999960 Required number is = 999960 – 4 = 999956
Statements:
Some P are Q
All Q are R
Some R are S
Conclusions:
I. Some R are not P
II. All R are P
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