Question
Which is the largest six digit number, which when
divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26 respectively.Solution
ATQ, LCM of 12, 15, 20, 24, 30 is 120 As we know, (12 – 8) = (15 – 11) = (20 – 16) = (24 – 20) = (30 – 26) = 4 As we know, 6 digit largest number = 999999 So, number divisible by 120 = 999999 – 39 = 999960 Required number is = 999960 – 4 = 999956
Sum of the two numbers is 49 and their HCF and LCM are 7 and 70, respectively. Find the sum of reciprocal of the given two numbers.
Three numbers a, b and c are co-prime to each other such that ab = 78 and bc = 65. Find the value of (a + b + c).
Ratio of two numbers 3:7 and their LCM is 840. Find the sum of the given two numbers.
The HCF of a^6 - 1 and a^4+ 2a^3- 2a-1 is
The greatest number of four digits which when divided by 6, 8, 10 leave remainders 3, 5, 7 respectively is:
Find the highest common factor (HCF) of (15/4) , (10/9) and (25/6)
Find the HCF of 245, 350 and 385.
The given numbers are in the ratio 2:5:6, and their highest common factor (HCF) is 15. Determine the least common multiple (LCM) of these numbers.
The ratio between three numbers is 7:3:2. Their HCF is given to be 5. Determine the LCM of the numbers.
The sum of two numbers is 99 and their HCF is 9. Total number of such pairs of numbers is?  Â
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