Question
If (a2 − b2)sin θ + 2ab cos θ
= a2 + b2, then tan θ =Solution
(a2 − b2) sin θ + 2ab cos θ = a2 + b2 divide it by a2 + b2 we get ((a2 − b2) sin θ) / (a2 + b2) + (2ab cos θ) / (a2 + b2) = 1 (sin2 θ + cos2 θ = 1) Here sin θ = (a2 − b2) / (a2 + b2) cos θ = 2ab / (a2 + b2) tan θ = (Sin θ) / (cos θ) = (a2 − b2) / 2ab
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