Answer-If (a2 − b2)sin θ + 2ab cos θ = a2 + b2, then tan θ =

a2 b2 sin 2ab cos a2 b2 divide it by a2 b2 we get a2 b2 sin a2 b2 2ab cos a2 b2 1 sin2 cos2 1 Here sin a2 b2 a2 b2 cos 2ab a2 b2 tan Sin cos a2 b2 2ab

Question

If (a2 − b2)sin θ + 2ab cos θ = a2 + b2, then tan θ =

A 2ab / (a^2 − b^2)

B (a^2 − b^2) / 2ab

C ab / (a^2 − b^2)

D (a^2 − b^2) / ab

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If (a2 − b2)sin θ + 2ab cos θ = a2 + b2, then tan θ =

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