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    Question

    If (a2 тИТ b2)sin ╬╕ + 2ab cos ╬╕

    = a2 + b2, then tan ╬╕ =
    A 2ab / (a^2 тИТ b^2) Correct Answer Incorrect Answer
    B (a^2 тИТ b^2) / 2ab Correct Answer Incorrect Answer
    C ab / (a^2 тИТ b^2) Correct Answer Incorrect Answer
    D (a^2 тИТ b^2) / ab Correct Answer Incorrect Answer

    Solution

    (a2 тИТ b2) sin ╬╕ + 2ab cos ╬╕ = a2 + b2 divide it by a2 + b2 we get ((a2 тИТ b2) sin ╬╕) / (a2 + b2) + (2ab cos ╬╕) / (a2 + b2) = 1 (sin2 ╬╕ + cos2 ╬╕ = 1) Here sin ╬╕ = (a2 тИТ b2) / (a2 + b2) cos ╬╕ = 2ab / (a2 + b2) tan ╬╕ = (Sin ╬╕) / (cos ╬╕) = (a2 тИТ b2) / 2ab

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