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    Question

    If (a2 − b2)sin θ + 2ab cos θ

    = a2 + b2, then tan θ =
    A 2ab / (a^2 − b^2) Correct Answer Incorrect Answer
    B (a^2 − b^2) / 2ab Correct Answer Incorrect Answer
    C ab / (a^2 − b^2) Correct Answer Incorrect Answer
    D (a^2 − b^2) / ab Correct Answer Incorrect Answer

    Solution

    (a2 − b2) sin θ + 2ab cos θ = a2 + b2 divide it by a2 + b2 we get ((a2 − b2) sin θ) / (a2 + b2) + (2ab cos θ) / (a2 + b2) = 1 (sin2 θ + cos2 θ = 1) Here sin θ = (a2 − b2) / (a2 + b2) cos θ = 2ab / (a2 + b2) tan θ = (Sin θ) / (cos θ) = (a2 − b2) / 2ab

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