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      Question

      If тАШ1x5629тАЩ is a six digit number which is divisible

      by 9, then which of the following can be the minimum value of тАШxтАЩ?
      A 6 Correct Answer Incorrect Answer
      B 5 Correct Answer Incorrect Answer
      C 4 Correct Answer Incorrect Answer

      Solution

      For a number to be divisible by тАШ9тАЩ, the sum of its digits must be divisible by тАШ9тАЩ.So, (1 + x + 5 + 6 + 2 + 9) = (23 + x)So, number after 23 which is multiple of 9 is 27,Therefore, minimum value of тАШxтАЩ = 27 тАУ 23 = 4

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