Train M, ‘x’ metres long crosses (x – 34) metres long platform in 15 seconds while train N having the length (x + 34) metres crosses the same platform in 20 seconds. If the speeds of both trains are same then find the value of ‘x’.
Total distance travelled by train M = (2x – 34) m Total distance travelled by train N = (x + 34 + x – 34) = 2x m According to question, => (2x – 34)/15 = 2x/20 => 40x – 680 = 30x => 10x = 680 => x = 68 m
(320 + 342 + 530 + 915) ÷ (20 + 22 – x + 18) = 43, then the value of x is:
?% of 140 + 16% of 250 = 62 × 12
17.5% of 400 – 24% of 150 = ?
672 ÷ 28 × 24 + 363 – 309 =?
60% of 250 + 14 × 10 - 210 = ?
(1296) -3/4 = ?
(3984 ÷ 24) x (5862 ÷ 40) = ?
√0.49 + √6.25 + √1.44 + √1.21 =? % of 125
808 ÷ (128)1/7 + 482 = 4 × ? + 846