Question
Train M, βxβ metres long crosses (x β 34) metres
long platform in 15 seconds while train N having the length (x + 34) metres crosses the same platform in 20 seconds. If the speeds of both trains are same then find the value of βxβ.Solution
Total distance travelled by train M = (2x β 34) m Total distance travelled by train N = (x + 34 + x β 34) = 2x m According to question, => (2x β 34)/15 = 2x/20 => 40x β 680 = 30x => 10x = 680 => x = 68 m
I. 5q = 7p + 21
II. 11q + 4p + 109 = 0
The equation x2 β px β 60 = 0, has two roots βaβ and βbβ such that (a β b) = 17 and p > 0. If a series starts with βpβ such...
I. xΒ² + 4x + 4 = 0
II. yΒ² - 8y + 16 = 0
I. 35x² + 83x + 36 = 0
II. 42y² + 53y + 15 = 0
I: x2Β + 31x + 228 = 0
II: y2Β + 3y β 108 = 0
I. 6x2 + 19x + 10 = 0
II. y2 + 10y + 25 = 0
I. 15b2 + 26b + 8 = 0
II. 20a2 + 7a - 6 = 0
I. 6p² + 17p + 12 = 0
II. 12q² - 25q + 7 = 0
I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
Solve the system:
3x + 2y = 16
4x β y = 9