New Click here to Enroll for SIDBI MSME Expert Classes by Experts

    Register

    Question

    Present ages of ‘A’, ‘B’ and ‘C’ are in the

    ratio 12:13:16, respectively. If present average age of ‘A’ and ‘C’ is 28 years, then find the age of ‘B’ when ‘C’ was 20 years old?
    A 13 years Correct Answer Incorrect Answer
    B 15 years Correct Answer Incorrect Answer
    C 14 years Correct Answer Incorrect Answer
    D 17 years Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the present ages of ‘A’, ‘B’ and ‘C’ be ‘12x’ years, ‘13x’ years and ‘16x’ years, respectively. ATQ; (16x + 12x) ÷ 2 = 28 Or, 28x = 56 So, x = 2 So, present age of ‘C’ = 16 × 2 = 32 years Present age of ‘B’ = 13 × 2 = 26 years Difference between the ages of ‘B’ and ‘C’ = 32 – 26 = 6 years So, age of ‘B’ when ‘C’ was 20 years old = 20 – 6 = 14 years

    Practice Next