Question
A boat moving downstream covers a distance of 200km in 5
hrs as long as to cover the same distance upstream it takes 10hrs. What will be the time taken by boat in still water to cover 360km.Solution
Let a boat moving in Downstream speed , (V + S) = 200/5 …..(1) = 40 km/h Upstream speed, (V - S) = 200/10…… (2) = 20 km/h Adding both equations (1) and (2) 2V= 60 km/h V= 30km/h Time in which boat will cover 360km in still water will be = 360/30 = 12 hrs.
4999.99 ÷ 10.25 + 379.99 - 160.25 = ?Â
47.78% of 499.98 + (19.89 × 7.76) = √? × 49.84
15.22 × 9.99 + 150.15 = ?
? + 163.99 – 108.01 = 25.01 × 6.98
What approximate value should come in the place of (?) in the following questions?
...
1749.8 * √255.77 - ?³ = 19.8 * 1300 + 1488.08What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
? = 25.08 + 14.99 × 25.07
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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