Question
Speed of a boat in still water is three times the speed
of the boat in upstream. If the boat takes 10 minutes to cover 28 km in downstream, then find the speed of the boat in still water.Solution
Let speed of the boat in still water be ‘3x’ km/h. Speed of the boat in upstream = 3x ÷ 3 = ‘x’ km/h Speed of the stream = 3x – x = ‘2x’ km/h Speed of the boat in downstream = 3x + 2x = ‘5x’ km/h ATQ; (28/10) × 60 = 168 So, 5x = 168 Or, x = 33.6 So, speed of the boat in still water = 3 × 33.6 = 100.8 km/h
- The sum and the difference of the L.C.M and H.C.F of two numbers are 486 and 342. If one of the numbers is 18, find the other number.
What should be the minimum number of chocolates so that when distributed among 3,4,5,6 and 7 children, 1,2,3,4 and 5 chocolates are left respectively?
The HCF of two numbers is 48, and their LCM is 1440. If one of the numbers is 576, find the other number.
A, B and C start running at the same time and at the same point in the same direction in a circular stadium. A completes a round in 720 seconds, B in 10...
The HCF of two numbers is 6 and their LCM is 84. If one of these numbers is 42, then the second number is:
If the product of two numbers is 350 and their HCF is 10, then find the LCM of the given two numbers.
Let N be the greatest number that will divide 72, 105, 138 leaving the same remainder in each case. Then sum of the digits in N is:
Find difference between the LCM and HCF of 14, 42 and 77.
HCF of two numbers 64 and 96 can be expressed in the form of (20m – 108) whereas LCM of these two numbers can be expressed in the form of (60n – 18)...
- The product of two numbers is 1344 and their L.C.M is 168. What is the H.C.F of the two numbers?
Relevant for Exams:
