Question
 A, B, and C run around a Circular track starting from
the same point simultaneously and in the same direction at 6 km/h, 12 km/h, and 18 km/h respectively. If the length of the track is 800 meters, when will A, B, and C meet at the starting point for the first time after they start the race?Solution
Time = Distance/Speed Time for A = 0.8/6 hours Time for B = 0.8/12 hours Time for C = 0.8/18 hours LCM of A, B, C = (LCM of numerator)/ (HCF of Denominator) = (LCM of 0.8,0.8,0.8)/(HCF of 6,12,18) = 0.8/6 hours 0.8/ 6hours = 10 minutes
‘P’ can finish a task in 36 days, while ‘Q’ can do the same task in (x + 4) days. If both work together and finish the task in 12 days, what is ...
P’s 2 days work is equal to Q’s 5 days work. If P and Q together can complete the work in 30 days then how much time Q will take to complete 60% of ...
Ratio of the work done by P, Q and R in one day is 6:4:7 respectively. They all together can complete the work in 45 days. Q and R worked on it for 27 d...
Ashish and Anil can do a piece of work in 20 days and 28 days respectively. Ashish completed 75% of the work. Find the time taken by Anil to complete th...
Komal and Seema individually can complete a task in ‘5a’ hours and ‘7a’ hours respectively. If they together can complete (4/5)th of the work in...
B is 20% more efficient than A. If B was 60% more efficient than A, then, B could complete the work in 18 days lesser than days taken by A. What fractio...
'A' is 40% less productive compared to 'B', who is 25% more productive than 'C'. Together, they can finish a task in 45 days. After 'B' and 'C' have col...
Sudhir is 4.5 times as efficient as Aarav. If they work together, they can complete a piece of work in 9 days. How many days will Aarav take to do the s...
Puneet and Qureshi together can complete (7/8)th of a piece of work in 9 days, Qureshi and Rohit together can complete (3/5)th of the work in 8 days and...
X can do a piece of work in 36 days. He worked at it for 6 days and then Y finished it in 20 days. In how many days can X and Y together finish the work...
