Question
A and B are travelling towards each other with a speed
of 10 km/hr and 20 km/hr. They started at same time and A covered 15 km less distance than B before meeting B. Find the distance between them before starting.Solution
Here time taken by both A and B is same, so the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 10:20 = 1:2 Let the distance covered by A and B be x km and 2x km respectively. According to question, => 2x – x = 15 => x = 15 Therefore, distance between them before starting = x + 2x = 3x = 45 km
Identify the logic of the below given series and given answer.
Series I :: 81, 89, 116, 241, (A), 1915
Series II :: (B), 204, 208, 4...
18Â Â Â Â Â Â Â Â Â Â 434Â Â Â Â Â Â Â Â 642Â Â Â Â Â Â Â Â 746Â Â Â Â Â Â Â Â 798Â Â Â Â Â Â Â Â ?
...10, 22, 46, ?, 130, 190
12, 20, 36, ?, 132, 260
8Â Â Â Â 20Â Â Â Â 36Â Â Â Â Â 56Â Â Â Â Â 80Â Â Â Â ?
If 152,   242,    x ,  332,   404,    314,
then find the value of (2x – 1)?
...21, 22, 48, 153, 628, ?
30Â Â Â Â Â Â 15Â Â Â Â Â Â Â 15Â Â Â Â Â Â Â 30 Â Â Â Â Â Â Â 120Â Â Â Â Â Â Â ?
...48Â Â Â Â 61 Â Â Â Â 76 Â Â Â Â 94Â Â Â Â 116 Â Â Â Â Â ?
If 4 2 x 1.5 0.5
Then, 1/3 x + 2.5 = ?
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