Question
Find the values of x and y if 0.1x + 0.05y = 20 and
0.3(x+2) +0.6y = 66.Solution
0.1x + 0.05y = 20 10x+5y =2000 2x+y=400        Y = 400-2x… (1) 0.3(x+2) +0.6y = 66. 3x+6+6y =660 3x+6y=654   put the value of Y 3x +6(400-2x) =654 3x +2400-12x =654 9x =1746 x =194. and putting the value of x in eq-1 we get, y = 400 - 2(194) = 400 - 388 = 12
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