Question
If ( p = 60 - q - r ) and ( pq + r(q + p) = 1080), then
find the value of ( p2 + q2 + r2).Solution
We have, ( p = 60 - q - r ) So, ( p + q + r = 60) And, ( pq + r(q + p) = 1080) Or, ( pq + qr + pr = 1080) Using, ( (p + q + r)2 = p2 + q2 + r2 + 2(pq + qr + pr) ) ((60)2 = (p2Â + q2Â + r2) + 2 x 1080) ((p2Â + q2Â + r2) = 3,600 - 2,160) ((p2Â + q2Â + r2) = 1440
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