Question
Before servicing, a car runs at a speed of 25 km/hr while after servicing, it runs at a speed of 50 km/h. After servicing the car covers a certain distance in 8 hours. How much time would the car have taken to cover the same distance when it was not serviced?
More Algebra Questions
- If x = 6 + 2√5, then the value of √x - (1/√x)?
- Question 2
- If 125x3 - 64y3 = (Ax + By) (Dy2 - Cx2 + 20xy) , then the value of A + C - 2B + 3D is:
- (a + 7)2 + (b – 2) 2 + (c + 3) 2 = 0, then find the value of 3a - 2b + c.
- If p = 34 - q - r and pq + r(q + p) = 289, then find the value of (p² + q² + r²).
- If, a 3 + b 3 = 485 and a + b = 5, then find the value of (1/a) + (1/b) .
- Find the value of ‘x’ in the given expression: (49/16)x × (64/343)x-1 = 4/7
- If 25% of Rs. 3,200 is equal to 40% of Rs. 'X', then find the value of 'X'.
- If 9x² + y² = 37 and xy=2, x, y>0, then the value of (27x³ + y³) is:
- If (x – 12) 3 + (x – 5) 3 + (x – 7) 3 = 3(x – 12)(x – 5)(x – 7) then find the value of (x 2 + 5x + 12)
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)