Question
If a = 56, b = c = 55, then find the value of a³ + b³
+ c³ – 3abc.Solution
We know, a³ + b³ + c³ – 3abc = (a + b + c){(a – b)² + (b – c)² + (c – a)²}/2 Or, a³ + b³ + c³ – 3abc = (56 + 55 + 55){(56 – 55)² + (55 – 55)² + (55 – 56)²}/2 = 166 × (2/2) = 166
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