Question
The graphs of the equations 3x-20y-2=0 and 11x-5y +61=0
intersect at P(a,b). What is the value of (a² + b² − ab)/(a² − b² + ab)?Solution
3x – 20y – 2 = 0 11x – 5y + 61 = 0 3x – 20y = 2 → (1) 11x – 5y = ΜΆ 61 → (2) 44x – 20y = 244→ (3) Equation (1) – (3) = (3x – 44x) = 2 + 244 = - 41x = 246 = [x = -6] Put x = - 6 in equation (1) -18 -20y = 2 = [y = -1] both equation intersect each other P(a,b) = P(x,y) a = 6, b = -1 on putting we get 31/41
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