If (x + y + z) = 68, (x/z) = (3/4) and (z/y) = (2/5), then find the value of ‘y’.
Let x = 3a So, z = 4a And, y = (5/2) × 4a = 10a Since, x + y + z = 68 So, 3a + 10a + 4a = 68 Or, 17a = 68 Or, a = 4 So, y = 10a = 10 × 4 = 40
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