Question
The present age of A is 3 times the age of
B. Eight years ago, the ratio of their ages was 5 : 1. Find B's present age.
Solution
Let B's present age = x Then A's present age = 3x Eight years ago, (3x - 8) / (x - 8) = 5 / 1 3x - 8 = 5x - 40 32 = 2x x = 16 Hence, B's present age = 16 years.
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