Question
There are three persons 'Amit', 'Bhuvan' and 'Cheetan'
such that 7 times the present age of 'Amit' is equal to 9 times the present age of 'Bhuvan' while 5 times the present age of 'Bhuvan' is equal 3 times the present age of 'Cheetan'. If the present ages of all three are integers and the age of 'Dheeraj' after 13 years will be equal to the sum of the minimum possible present ages of 'Amit', 'Bhuvan' and 'Cheetan', together, then find the present age of 'Dheeraj'.Solution
Let the present ages of 'Amit', 'Bhuvan' and 'Cheetan' be 'x' years, 'y' years and 'z' years respectively According to the question, 7x = 9y Or, x:y = 9:7 = 27:21 Also, 5y = 3z Or, y:z = 3:5 = 21:35 Let 'x' and 'y' be 27a and 21a, respectively Therefore, 'z' = 21a X (35/21) = 35a Therefore, x:y:z = 27:21:35 Therefore, age of 'Dheeraj' 13 years hence from now = 27 + 21 + 35 = 83 years Therefore, required age = 83 - 13 = 70 years
116 x (2/3)% of 420 + 666 x (2/3)% of 186 = 457 x (1/7)% of 126 + 555 x (5/9)% of 198 + ?
108² + 99 X 98² =?
...2945 – 1508 + 3454 = ? + 2255
15 * 12 + 35% of 80 + 70% of 130 = ?
What will come in the place of question mark (?) in the given expression?
65% of 900 - 45% of 600 = ? X 3Â
√225 + 27 × 10 + ? = 320
46% of 13/92 × 24/91 × 3500 =?
What is 12% of 4% of 7% of 2 x 106 ?
- What will come in place of (?), in the given expression.
125% of 96 + 33% of 300 = ?
