Question
There are three persons 'Amit', 'Bhuvan' and 'Cheetan'
such that 7 times the present age of 'Amit' is equal to 9 times the present age of 'Bhuvan' while 5 times the present age of 'Bhuvan' is equal 3 times the present age of 'Cheetan'. If the present ages of all three are integers and the age of 'Dheeraj' after 13 years will be equal to the sum of the minimum possible present ages of 'Amit', 'Bhuvan' and 'Cheetan', together, then find the present age of 'Dheeraj'.Solution
Let the present ages of 'Amit', 'Bhuvan' and 'Cheetan' be 'x' years, 'y' years and 'z' years respectively According to the question, 7x = 9y Or, x:y = 9:7 = 27:21 Also, 5y = 3z Or, y:z = 3:5 = 21:35 Let 'x' and 'y' be 27a and 21a, respectively Therefore, 'z' = 21a X (35/21) = 35a Therefore, x:y:z = 27:21:35 Therefore, age of 'Dheeraj' 13 years hence from now = 27 + 21 + 35 = 83 years Therefore, required age = 83 - 13 = 70 years
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
√323.89  × (3.20) ÷ 9.02 =?
24.11% of 249.99 + √143.97 ÷ 12.02 = ?
 5983.987 + 59832.999 – 598.873 = ?
(100.01% of 44.89) ÷ 14.98 = √? - √48.98
(5.013 – 30.04) = ? + 11.98% of 4799.98
(4096)1/3 × 10.11 × 11.97 ÷ 24.32 = ? + 15.022
- √81.45 + √225.60 + 49.89% of (520.43 + 22.13% of 131.45) = ?
40.024 of 54.89% of 19.9 = ? × √(2661.98/22.09)Â
Find the approximate value of Question mark(?) for given equation.Â
135.86% of 249.99 + 24.95 × 14.03 ÷ 2.01 = ?
