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Start learning 50% faster. Sign in nowLet the present ages of Rahul and his son be x and y respectively. 2n years ago, => x – 2n = 4(y – 2n) => x = 4y – 6n ------ (i) n years ago, => x - n = 3(y – n) => x = 3y – 2n ------ (ii) Solving (i) and (ii) we get, => y = 4n => x = 4 × 4n – 6n = 10n Now n years later, => x + n + y + n = 80 => 4n + n + 10n + n = 80 => 16n = 80 => n = 5 Required difference = 10n – 4n = 6n = 30 years
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