Question
The present ages of a father and his son are in the ratio 7 : 3. After 10 years, the ratio of their ages will become 9 : 5. What is the present age of the father?
Solution
Let present ages be 7x (father) and 3x (son). After 10 years: (7x + 10) / (3x + 10) = 9 / 5 5(7x + 10) = 9(3x + 10) 35x + 50 = 27x + 90 8x = 40 x = 5 Father’s present age = 7x = 7 × 5 = 35 years
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