Question
Present age of βDβ is 45% more than that of βEβ.
9 years ago, βDβ was 1.75 times as old as βEβ. Find the present age of βEβ.Solution
Let the present age of βEβ be βxβ years
Therefore, present age of βDβ = 1.45x years
ATQ;
(1.45x β 9) = 1.75 Γ (x β 9)
Or, 1.45x β 9 = 1.75x β 15.75
Or, 6.75 = 0.3x
Or, x = 22.5
Therefore, present age of βEβ = 22.5 years
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