Seema’s present age is 1(1/2) times of her marriage. She married 12 years ago. Now she has a daughter whose age is 2 more than one third of her age at the time of marriage. Find the age of the daughter?
Let Seema’s age at the time of her marriage be x Then, present age of Seema = 3x/2 According to the question x + 12 = 3x/2 3x/2 - x = 12 x/2 = 12 x = 24 years Now, daughter’s age = 1x/3 + 2 = (1/3) x 24 + 2 = 8 + 2 = 10 years
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