Question
18 years ago the average age of a family of four members was 45 years. Two children were born in that span of 18 years. The present average age of the family remained unchanged. Among the two children who were born in between the 18 years, if the older child at present is 12 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child?
More Age Questions
- The age ratio of Kiran and Meena 3 years ago was 3:4. In 9 years from now, the ratio of their ages will be 5:6. What is the present age of Meena?
- Four years ago, the combined ages of Linda and Joan was 56 years. Four years hence, the ratio of their ages will be 4:5. Find the current age of Linda.
- The ratio of the present ages of Aarti and Meena is 3:2. If Aarti’s age three years ago was equal to Meena’s age five years later, what is Aarti’s current ...
- The present ages of a father and his son are in the ratio 7 : 3. If 5 years ago the father was three times as old as his son, what is the sum of their pres...
- Amit age after 20 years will be 4 times his age 4 years back. What is the present age of Amit?
- Present average age of 4 friends: ‘A’, ‘B’, ‘C’ and ‘D’ is 30 years. If their ages are in the arithmetic progression in the same order and ‘D’ is 4 years o...
- Father’s age : Son’s age = 5 : 2. After 12 years, ratio becomes 7 : 4. Find present ages.
- A’s age is 150% of what he was 6 years ago, But 50% of what it will be after 6 years. What is his present age?
- The present ages of A and B are such that 8 years ago, the ratio of A’s age to B’s age was 7 : 5. Four years from now, the ratio of their ages will be 11 :...
- Shalini is younger than Rashi by 4 years. If the ratio of Shalini and Rashi ages is 8:9 respectively, then find the age of Shalini.
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
