Question
The sum of the ages of a father and his son is 60 years.
15 years ago, the father was five times as old as the son. What is the present age of the father?Solution
Let the son’s present age be x. Then, father’s age = 60 - x. 15 years ago, father’s age = (60 - x) - 15, and son’s age = x - 15. (60 - x - 15) = 5(x - 15). Solving this: 45 - x = 5x - 75, 120 = 6x, x = 20. Father’s age = 60 - 20 = 40 years. Correct Option: b) 40 years
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