Question
Present ages of P and Q are in the ratio 5:7
respectively. If Q’s age, 11 years hence from now will be 5 times of P’s age, 5 years ago from now, then find the present age of Q.Solution
Let the present ages of P and Q be 5x and 7x years respectively. According to the question, => (7x + 11) = 5 ×  (5x – 5) => 7x + 11 = 25x – 25 => 18x = 36 => x = 2 Therefore, the present age of Q = 7x = 14 years
I. 2x2 - 9 x + 9 = 0Â
II. 2y2 - 7 y + 3 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 2x² - 15x  + 13 = 0
II. 3y² - 6y + 3 = 0
I. x²= 961Â
II. y= √961
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
I. 27x6-152x3+125=0
II. 216y6Â -91y3+8=0
I. 4x² - 21x + 20 = 0
II. 8y² - 22y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
