Question
Five years ago, the ratio of age of 'A' to 'B' was 4:5.
After ten years, the ratio of age of 'A' to 'B' will be 7:8. Find the current age of 'C' who is 6 years younger than 'B'.Solution
ATQ,
Let the age of 'A' and 'B', five years ago be '4a' and '5a' years, respectively.
So, (4a + 5 + 10) : (5a + 5 + 10) = 7:8
Or, 8 × (4a + 15) = 7 × (5a + 15)
Or, 32a + 120 = 35a + 105
Or, 3a = 15
So, a = 5
Required age = 5 × 5 + 5 - 6 = 24 years
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 19Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 70...
6000 3002 1503 ? 378.75 191.375 97.6875
...If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...8   24    12    ?   18     54
3 ? 7 16 71 346
...104   106   110   113   ?   126
12, 18, 28, 42, 52, ?
18Â Â Â Â Â Â Â Â Â Â Â Â 29 Â Â Â Â Â Â Â Â Â Â Â Â Â Â 51 Â Â Â Â Â Â Â Â 84 Â Â Â Â Â Â Â Â 128 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 182
5, 8, 17, ?, 37, 48
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
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