Question
4 years back, the combined age of 'Arvind' and 'Chirag'
was 9 years lower than the current total age of 'Arvind' and 'Bishma'. Seven years from now, the age total of 'Bishma' and 'Chirag' will be 63 years. What is 'Chirag's' current age?Solution
ATQ, Seven years hence from now, the sum of ages of 'Bishma' and 'Chirag' will be 63 years. So, sum of present age of 'Bishma' and 'Chirag' = 63 - (2 × 7) = 49 years Let present age of 'Chirag' be 'p' years. So, present age of 'Bishma' = (49 - p) years Let the sum of present ages of 'Arvind' and 'Bishma' be 'q' years. So, the present age of 'Arvind' = q - (49 - p) = (q + p - 49) years Four years ago from now, sum of ages of 'Arvind' and 'Chirag' was 9 years less than the sum of present ages of 'Arvind' and 'Bishma'. So, ATQ; (q + p - 49 - 4) + (p - 4) + 9 = q Or, q + 2p - 48 = q Or, 2p = 48 So, p = (48/2) = 24 So the present age of 'Chirag' = p = 24 years
If (2sin A + cos A) = 3sin A, then find the value of cot A.
If 4cos2x - 3 = 0, and (0° > x > 90°), then find the value of 'x'.
- From the top of a tower, the angle of depression to the top of a man's head is 60°. The man is 4 feet tall and is standing 20 feet away from the base of t...
Find the value of tan(75°) using the identity for tan(A+B).
If x = 4 cos A + 5 sin A snd y = 4 sin A – 5 cos A, then the value of x2+y2 is :
If √3 tan x = 3, then the value of x:
∆ PQR is right-angled at Q. If ∠R = 60º, then find the value of cosec P.
What is the value of sin(B – C) cos(A – D) + sin(A – B) cos(C – D) + sin(C – A) cos(B – D)?
If tanθ – cotθ = a and cosθ + sinθ = b, then (b2 –1)(a2 + 4) = ?