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Let Rohan's present age be ‘x’ years. Then, Rohan’s father’s age will be ‘7x/2’ years. Also, let Rohan’s present age be ‘3y’ years. So, Rohan’s mother’s present age will be ‘10y’ years. We have, x = 3y and 7x/2 − 6 = 10y. Substitute x = 3y: 7(3y)/2 − 6 = 10y. Simplifying, (21y/2) − 6=10 Multiply the equation by 2 to eliminate the fraction: 21y − 12 = 20y. Simplifying further: 21y − 20y = 12, y = 12. So, Rohan’s present age = x = 3y = 36 years.
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
Solve.
15.73 +13.25 +16.73 – 28.71 = 5 ×?
If √3n 729, then the value of n is equal to:
?% of 120 × 3√343 = 42 × 20
(64/25)? × (125/512)?-1 = 5/8
(-251 × 21 × -12) ÷ ? = 158.13