Question
10 years ago, the ratio of the ages of Maya and Neil was
4:3. The present age of Jake is 10 years more than one-fourth of Neil’s present age. Find the present age of Jake, if Maya’s age in 6 years will be 40 years.ÂSolution
Maya and Neil's ages 10 years ago = 4x and 3x Present ages = 4x + 10, 3x + 10 Maya's present age = 40 – 6 = 34 years → 4x = 34 – 10 = 24 → x = 6 Neil's present age = 3(6) + 10 = 28 Jake's present age = (1/4) * 28 + 10 = 17 years
What will come in the place of question mark (?) in the given expression?
(63 - ?) ÷ 5 + √625 = 19 X (9 - 6)
- What will come in place of (?), in the given expression.
(4² + 6²) × 2 = ? What will come in the place of question mark (?) in the given expression?
(40/25) X 80 - ? = 45% of 300 - 5525.6% of 250 + √? = 119
1220 ÷ 61 ÷ 5 + 450 of 20% - 70 = √ ?
Simplify the expression:
(5x + 15) / (x² + 3x)
What will come in the place of question mark (?) in the given expression?Â
435 ÷ 29 X 792 ÷ 44 = √(? + 14) + 35 + 221 ÷ 17
...192.251 + 326.233 + 125.021 + 19.273 = ?
36% of 640 – 12.5% of 352 + 25% of 640 = ? – 48% of 432
Simplify the following expressions and choose the correct option.
18 * 15 - {3/5 of 250 + 72}
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