Question
Present ages of 'A' and 'B' are in the ratio 3:5,
respectively. If B's age, 8 years hence from now will be 3 times of A's age, 2 years ago from now, then find the present age of 'A'.Solution
Let the present ages of 'A' and 'B' be '3x' years and '5x' years, respectively. ATQ; (5x + 8) = 3 x (3x - 2) Or, 5x + 8 = 9x - 6 Or, 4x = 14 x = 3.5 So, present age of 'A' = 3 x 3.5 = 10.5 years
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