Question
P says to Q “I am four times as old as you were
when I was as old as you are”. The difference between their ages is 15 years. Find the sum of their ages?Solution
P says to Q “I am four times as old as you were when I was as old as you are”. P = 4[Q- (P-Q)] P = 4Q – 4P + 4Q 5P = 8Q ………………….(i) P – Q = 15 …………………(ii) By solving (i) and (ii), we get Q = 25 & P = 40 Therefore, sum of their ages = 40 +25 = 65 years
11   33   66   112   173    ?  . Â
324 322 640 1914 7648 ? 229368
...Find sum of first n terms: 2 + 6 + 12 + 20 + 30 + …
351Â Â Â 261Â Â Â 181Â Â Â 111Â Â Â 51Â Â Â ?
If Series II follows the same pattern as Series I, then determine the value of 'p'.
Series I: 36, 38, 48, 78, 146, 276
Series II: 49, __, __, __, __, p.
17                          26                          37                   �...
32, 8, 4, ?, 3, 3.75
40    42    87    266    ?     5366
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
7Â Â Â Â Â Â 15Â Â Â Â Â Â Â 31Â Â Â Â Â Â 63Â Â Â Â Â Â 127Â Â Â Â Â Â ?
...
