Question
Present ages of 'A' and 'B' are in the ratio 3:5,
respectively. If B's age, 11 years hence from now will be 5 times of A's age, 18 years ago from now, then find the present age of 'A'.Solution
Let the present ages of 'A' and 'B' be '3x' years and '5x' years, respectively. ATQ; (5x + 11) = 5 x (3x - 18) Or, 5x + 11 = 15x - 90 Or, 10x = 101 x = 10.1 So, present age of 'A' = 3 x 10.1 = 30.3 years
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