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Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.50 = ‘1.50x’ years ATQ; (x + 20) + 16 = (1.50x + 20) Or, x + 36 = 1.50x + 20 Or, 16 = 0.5x Or, x = 32 So, present age of ‘B’ = 32 years And, present age of ‘A’ = 32 + 16 = 48 years Required sum = 32 + 48 = 80 years
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