Question
Present age of βAβ is 50% more than that of βBβ.
If 20 years hence from now, βBβ will be 16 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.50 = β1.50xβ years ATQ; (x + 20) + 16 = (1.50x + 20) Or, x + 36 = 1.50x + 20 Or, 16 = 0.5x Or, x = 32 So, present age of βBβ = 32 years And, present age of βAβ = 32 + 16 = 48 years Required sum = 32 + 48 = 80 years
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