Question
Present age of ‘A’ is 50% more than that of ‘B’.
If 20 years hence from now, ‘B’ will be 16 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.50 = ‘1.50x’ years ATQ; (x + 20) + 16 = (1.50x + 20) Or, x + 36 = 1.50x + 20 Or, 16 = 0.5x Or, x = 32 So, present age of ‘B’ = 32 years And, present age of ‘A’ = 32 + 16 = 48 years Required sum = 32 + 48 = 80 years
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