Question
7 years ago, the average age of a family of four persons
was 30 years. In between these 7 years the family adopted a girl. Now at present the average age of the family is same as it was 7 years ago. Find the present age of the girl. TYPE 35Solution
Sum of the present age of the family excluding girl = 4 x (30 + 7) = 148 years Sum of the present age of the family including girl = 5 x 30 = 150 years Present age of the girl = 150 – 148 = 2 years
 (108.999)² - (102.001)²=?
30.22% of (61.9 × 5.01) + 69.97 =?Â
2875.45 + ? – 2762.19 = 2145.72 – 1956.63
( 1000)1/3  × 10.11 × 4.97 ÷ 10.32 =? – 15.022
Find the approximate value of Question mark(?) for given equation.Â
104.85% of 479.89 – √2400.91 + (71.92 ÷ 6.03) × 24.85 = ?
...1240.04 – 360.18 + 449.98 ÷ 15.06 = ?
16.02% of (189.15 + 210.87) + 9.02³ - (7.95 of 4.98) = ? of (37.95 - 19.89)
? + 157.99 – 101.01 = 25.01 × 5.98
What will be the approximate value of the following questions.
(1/2 of 959.90 + 69.69% of 359.79) ÷ (√63.94 × 2/5 of 250.14) = ?